Question

in the adjoining figure is a circle with Centre O if angle BAC is equal to 60 degree and Angle DCB is equal TO 100 degree then find angle DBC

Answer 1

Answer:

Step-by-step explanation:

Ans is 20 degree

Answer 2

Hey mate here is your answer,
In the given figure
angle BAC = angle BDC [ angle in the same segment]
angle BAC= angle BDC=60°
and angle DBC = 100° ( given )
In ∆BCD,
= angle BDC + angle DCB + angle DBC = 180°( by Angle sum property of ∆ )
Therefore,
= 60° + 100° + angle DBC = 180°
= 160° + angle DBC = 180°
= angle DBC = 180° - 160°
= angle DBC = 20°
hope it helps you