Question

In the adjoining figure, triangle ABC is an isosceles triangle with AB=AC and AD is one of it's altitides. Prove that triangle ABD=~ADC

Answer 1

Step-by-step explanation:

In ∆ ABD AND ∆ ADC

1. ANGLE ADB = ANGLE ADC ..... EACH 90°

2. ANGLE BAD = ANGLE DAC .... COMMAN

ANGLE

THEREFORE , BY AA TEST OF SIMILARITY ,

∆ ABD =~ ∆ ACD ... PROVED

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