Question

in the adjoining figure xy parallel to BC a x is equals to minus 3 by x is equal to 2 p - 2 and a bi bi Si Y is equals to 1 by 4 find the value of p​

Answer 1

Step-by-step explanation:

Given In the adjoining figure xy parallel to BC Ax is equal to P minus BX is equal to 2 p - 2 and AY is equal to1 CY = 4 find the value of p

• Given XY is parallel to BC, AX = P – 3, BX = 2p – 2, AY = 1, CY = 4
• We know that from proportionality theorem, if a intersect two sides of a triangle and parallel to third side, then it divides those sides proportionally.
• Using this theorem we get  
• AX / XB = AY / YC
• Substituting the given values we get
• P – 3 / 2 P – 2 = 1/4  
• Cross multiplying, we get
• 4 (P – 3) = 1(2P – 2)
• 4P – 12 = 2P – 2
• So 4P – 2P = 12 – 2
• So 2P = 10
• So P = 5

Therefore the value of P is 5

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Answer 2

Answer:

P=5

Step-by-step explanation:

Given: In △ABC, XY || BC ∴

XB/AX = YC/AY (∵ Thales theorem)

2p−2/p−3​ =1/4

⇒4(p−3)=1(2p−2)

⇒4p−12=2p−2

⇒2p=10 ∴p=5

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