Question

in the circuit shown in the following figure the potential difference across three microfarad capacitor is

Answer 1

Answer:

6 volt is the answer.........

Answer 2

Given that,

Capacitor C₁ = 3μF

Capacitor C₂ = 5μF

Potential V₁= 4 V

Potential V₂= 20 V

We need to calculate the net potential

Using formula for net potential

$V=V_{2}-V_{1}$

Put the value into the formula

$V=20-4$

$V=16\ V$

We need to calculate the net capacitor

Using parallel formula

$C_{eq}=C_{1}+C_{2}$

Put the value into the formula

$C_{eq}=3+5$

$C_{eq}=8\ \mu F$

We need to calculate the potential difference across 3μF

Using formula of potential difference

$V'=\dfrac{C_{1}}{C_{eq}}\times V_{net}$

Put the value into the formula

$V'=\dfrac{3}{8}\times16$

$V'=6\ V$

Hence, The potential difference across 3μF is 6 V.

(2) is correct option.