Question

In the cylinderical container , the base radius is 8cm .If the height of the water level is 20cm .Find the volume of the water in the container (1m^3=1000l)

Answer 1

Solution :

In this given cylindrical container :

> Radius of Base = 8 cm

> Maximum Height of Water Level = 20 cm.

To Find : Maximum volume of water which can be present in the container .

For any cylinder having the base radius as r cm and the height as h cm :

The volume of the cylinder is П r^2 h

Substituting the given values :

> pi ( 8 )^2 * 20

> 64 pi x 20

> 128 pi

This is in cm^3 .

It is given that :

1 m^3 = 1000 l

But, 1 m^3 = 1000 cm^3

> 1000 cm^3 = 1000 l

> 1 cm^3 = 1 l

Hence, the required volume of water in the container is 128 pi litres.

This is the answer .

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Answer 2

$\large{\underline{\underline{\textsf{\maltese\: {\red{Given :-}}}}}}$

☞ Radius (r) = 8cm

☞ Height (h) = 20cm

$\large{\underline{\underline{\textsf{\maltese\: {\red{To Find :-}}}}}}$

☞ Volume (v) of the water in the container = ?

$\large{\underline{\underline{\textsf{\maltese\: {\red{Solution :-}}}}}}$

Volume of cylinder = πr²h

✿ Putting the values.

Volume of cylinder = πr²h

⇒ Volume of cylinder = $\dfrac{22}{7}$ × 8 × 8 × 20

⇒ Volume of cylinder = 4,022.8cm³

✿ Now we change the unit.

1000cm³ = 1L

⇒ 1cm³ = $\dfrac{1}{1000}$ L

⇒ 4,022.8 cm³ = $\dfrac{1}{1000}$ × 4,022.8 L

⇒ 4,022.8cm³ = 4.0228 L

Therefore, the volume of the water in the container is 4.0228 litres.