Question

In the equation 5=(×+2)^2,what are the values of a,b and c?

Answer 1

Answer:

A = 5, B = (-9) and C = 4

Step-by-step explanation:

$5 = ( x + {2})^{2} \\ 5 = {x}^{2} + 4 \\ 5 + {x}^{2} + 4 = 0 \\ 9 + {x}^{2} = 0 \\ 0 = 9 + {x}^{2} \\ {x}^{2} = ( - 9) \\ x = \frac{( - 9)}{2} \\ x = 4.5 \\ \\ 5 = {(x + 2)}^2 \\ 5 = {( 4.5 + 2)}^{2} \\ 5 + (- 9) + 4 = 0 \\ a = 5 \: \: \\ b = ( - 9) \: \: \\ c = 4$

Answer 2

Step-by-step explanation:

5 = (x + 2)^2

5= x^2 + 2^2

5= x^2 + 4

5 - 4 = x^2

1 = x^2

Taking square root on both sides:

$\sqrt[2]{1} = \sqrt[2]{x}$

$1 = x$