Question

In the equation int (dx)/sqrt(2ax - x^(2) ) = a^(2) sin ^(-1) [(x)/(a) - 1]. Find the value of n .

Answer 1

Hence the value of n = 0

Explanation:

x^2  = [L^2]

2ax =  [L^2]

a =  [L^2] /  [L] =  [L]

d2 =  [L]

√2ax.x^2 =  [L]

L.H.S =  [L] /  [L] =  [Lo]

a^n =  [Lo]

a^n = 1

n = 0

Hence the value of n = 0