Question

In the experiment to determine the period of simple pendulum of length 1m, it is attached of different spherical bobs of radii r1 and r2. The two spherical bobs....

Answer 1

Given by

In experiment to determine the period of simple pendulum of length=1m

two spherical bobs uniform mass distribution .relative difference is 5*10^-4 kg  radii difference | r1 -r2 |

time period simple pendulum   T=2π√l/g

l=length of pendulum , g=due to gravity is acceleration thus

T=2π√l/g⇒Ta√l

diff both sides  with respect to t

ΔT/T= (1/2) Δl/l  ,change in length Δl =| r1-r2 |

 relative difference of length is  5*10^-4 so

5*10^-4=1/2(r1-r2)

⇒r1-r2=10*10^-4 m

 r1-r2=10*10-3 m

⇒r1-r2=10*10-1 cm  

r1-r2=0.1 cm   answer ...

Answer 2

Answer:

T∝l√l=1

ΔTl=12ΔllΔl=r1−r2

5×10−4=12r1−r21

r1−r2=10×10−4

10−3m=10−1cm−0.1cm