Question

In the isothermal expansion of 10 g of the gas from volume v to 2v the work done by the gas is 575j

Answer 1

Work done by the gas = 575 J.

Mass of the Gas = 10 g.

Since, the expansion is Isothermal, therefore,

Work Done = -2.303nrTlog(V₂/V₁)

Work done = -2.303 × P × V log2

575 = -2.303 × PV  × 0.3010

PV = 829.5

P = 829.5/V

This will be the pressure.

If you thinks that we can find the constant temperature, but the name of the Gas is not given, thus we don't know the molar mass of the gas, hence no. of moles cannot be find. If you have molar mass of gas, then substitute the nRT in place of the PV.

Hope it helps.

Answer 2

Work done by the gas = 575 J.

Mass of the Gas = 10 g.

Since, the expansion is Isothermal, therefore,

Work Done = -2.303nrTlog(V₂/V₁)

Work done = -2.303 × P × V log2

575 = -2.303 × PV  × 0.3010

PV = 829.5

P = 829.5/V

This will be the pressure.