Question

in the fig, a quadrilateral ABCD is the circumscribe a circle with AB=3cm and CD=8 CM , Then AD+BC=​

Answer 1

Step-by-step explanation:

Step-by-step

PROVE THAT:AB+CD=AD+BC

PROOF:

AP=AS  -----1

PB=BQ  -----2      [TANGENTS DRAWN FROM

CR=CQ  -----3       EXTERNAL POINTS ARE

DR=DS   -----4            EQUAL]

                         AB+CD= AP+PB+CR+DR  [FROM FIG]

                                        = AS+BQ+CQ+DS   [FROM 1,2,3,4]

                                      = (AS+DS)+(BQ+CQ)

                                      = AD+BC