in the fig
abcd is a cyclic quadrilateral in which ac and bd diagonal.if angle abc is 55 and angle bac is 45 find angle bda
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heritageindiaom:
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triangle ABC,by angle sum property
45+55+angle 1 =180
angle 1=80
angle 1=angle 2
angle 2=80
angle bda=80
45+55+angle 1 =180
angle 1=80
angle 1=angle 2
angle 2=80
angle bda=80
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Answered by
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here's the answer^.^
p.s I'm sorry for the mistake earlier(•ω•)
p.s I'm sorry for the mistake earlier(•ω•)
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