In the fig. PA and PB are two tangents drawn to a circle of centre O .A chord BC is drawn parallel to tangents PA. If angles p =40 and AB=AC find angles:ABC, BCA and BAC
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Hey mate here is your answer...........
In triangle PAB,
PA = PB
<PBA=<PAB-------1
Now, In triangle PBA, we get
<PBA + <PAB + < APB = 180
<PAB + <PAB + 40 = 180(using 1)
2<PAB= 180 - 40
<PAB = 70
Now, BC// PA
<ABC = <PAC(Alternate angles)
<ABC = 70
AB = AC
<BCA = <ABC
<BCA = 70
Now, <BAC + <ABC + <BCA = 180
<BAC + 70 + 70 = 180
<BAC = 40
HOPE IT HELP YOU .............................
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