In the fig., PQ 24 cm, QR = 26 cm, PAR= 90°, PA = 6 cm and AR 8 cm. FindQPR.
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It's pretty easy if u think it out.
The angle does look like 90degrees. And almost wherever there is any mention of 90degree angle. Pythagoras Theorem comes into play.
As PAR=90
PR=√PA^2+AR^2
PR=√100
PR=10cm
Using Pythagoras Theorem,
Prove that 10^2+24^2=26^2
This satisfies the Pythagoras Theorem and hence QPR=90 degrees
Hope it helps.
Please mark as brainliest...
The angle does look like 90degrees. And almost wherever there is any mention of 90degree angle. Pythagoras Theorem comes into play.
As PAR=90
PR=√PA^2+AR^2
PR=√100
PR=10cm
Using Pythagoras Theorem,
Prove that 10^2+24^2=26^2
This satisfies the Pythagoras Theorem and hence QPR=90 degrees
Hope it helps.
Please mark as brainliest...
GeniusManish:
i am unable to mark you brainliest
i am willing but the opition is isn't shaowing up
Only if 2 or more people hav answered you an mark as brainliest.
Anyways. Thanks for trying;-)
now u can mark
pls dont see my ans its copied from above
Thanx a lot Antony... Really appreciate your concern....
Thanks
No probs
Answered by
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Answer:
s PAR=90
PR=√PA^2+AR^2
PR=√100
PR=10cm
Using Pythagoras Theorem,
Prove that 10^2+24^2=26^2
This satisfies the Pythagoras Theorem and hence QPR=90 degrees
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