In the figuee AB || CD , find the value of X
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Answer:
From E, draw EF || AB || CD. EF || CD and CE is the transversal.
∴∠DCE+∠CEF=180
o
[∵ Co-interior angles]
⇒x
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+∠CEF=180
o
⇒∠CEF=(180−x
o
)
Again, EF || AB and AE is the transversal.
∠BAE+∠AEF=180
o
[∵ Co-interior angles]
⇒105
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+∠AEC+∠CEF=180
o
⇒105
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+25
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+(180
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−x
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)=180
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⇒310−x
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=180
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Hence, x=130
o
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