IN THE FIGURE 10.13, ANGLE A = 75° AND CE || AB. IF ANGLE ECD = 40°, FIND THE OTHER TWO ANGLES OF THE TRIANGLE ABC.
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Answer:as AB is parallel to CEBAC=ECA=75 { alternate interior angles } ... If ZECD = 40°, find the other two; of the triangle ABC. 750 40° Fig. 10.13. 2 ... ACD=BAC+CBA{exterior angle
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