Question

In the figure, A-D-C and B-E-C. seg DE || side AB. If AD=5, DC = 3,
BC = 6.4, then find BE and EC.​

Answer 1

Answer:

DE||AB

therefore

$\frac{ce}{eb} = \frac{cd}{ad}$

$\frac{6.4 - x}{x} = \frac{3}{5}$

$5(6.4 - x) = 3x$

$32 - 5x = 3x$

$8x = 32 \\ x = 4$

$ce = 6.4 - 4 = 2.4 \\ eb = 4$

that's is your answer