Question

In the figure AB||CD, ABE = 130°, BED = 20° then find EDC?​

Answer 1

Answer:

ABE = 130°

ABF = 180° (Straight line)

EBF = 180-130

= 50°

BED = 20°

SO, BEF + BFE + EBF =180° (ANGLE SUM PROPERTY OF TRIANGLE)

BFE=180-(20+50)

BFE=180-70

BFE= 110°

BFE = EDC =110° ( ANGLE AT SAME SIDE OF TRANSVERSAL ARE EQUAL)

so, < EDC = 110°