In the figure angle EBC = 115 degree and Angle DAB = 100 degree. Find angle ACB.
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ans.is angle ACB= 35°
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angle DAB and angle BAC form a linear pair,
DAB+BAC=180°[linear pair]
100°+BAC=180°
BAC=180°-100°
BAC=80°
Angle EBC and Angle CBA Form a linear pair
EBC+CBA=180°[linear pair]
115°+CBA=180°
CBA=180°-115°
CBA=65°
CBA+BAC+ACB=180°[Angle sum property of triangle]
65°+80°+ACB=180°
145°+ACB=180°
ACB=180°-145°
ACB=35°
DAB+BAC=180°[linear pair]
100°+BAC=180°
BAC=180°-100°
BAC=80°
Angle EBC and Angle CBA Form a linear pair
EBC+CBA=180°[linear pair]
115°+CBA=180°
CBA=180°-115°
CBA=65°
CBA+BAC+ACB=180°[Angle sum property of triangle]
65°+80°+ACB=180°
145°+ACB=180°
ACB=180°-145°
ACB=35°
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