Question

In the figure, AOC and BOC form a linear pair, If a - 2b = 30', find a and b?

Answer 1

Answer:

Hola‼........❤✌

If, a-2b = 30°

Angle AOC = a°, Angle BOC = b°

a+b = 180°........(1)

Given, a-2b = 30°....(2)

By subtracting 1 & 2

a+b + a -2 b = 180°-30°

=> b = 50°

Hence, a-2b = 30°

=> a - 2×50° = 30°

=> a = 130°

Hope it’s helpful...... ☺

Answer 2

Answer:

a = 130° ; b = 50°

Step-by-step explanation:

∠AOC + ∠COB = 180°

∠AOC = ∠a

∠COB = ∠b

∴∠a + ∠b = 180° (equation 1)

a - 2b = 30° (given in question) (equation 2)

a = 30 + 2b

( a from the first equation and second equation are cancelled by each other )

180 = 30 + 2b + b

180 = 30 + 3b

180 - 30 = 3b

150 = 3b

150/3 = b

50 = b

∵ a + b = 180

    a = 180 - b

    a = 180 - 50

    a = 130

║∴ a = 130° & b = 50°║