In the figure, BP:PQ:QC=1:2:1, ar(PAQ) =8cm.
i) Find area of Triangle ABP
ii) Find area of Triangle ABC
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4
Answer:
Height of all triangles ABP, PAQ, ABC are same. Only change in base. so,
i) Area of ABP = 8/2 = 4 cm².
ii) Area of ABC = 8×2 = 16 cm²
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0
Answer:
if the triangle PAQ is 8 where the ratio is 1:2:1
that means half of 8 which is 4
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