In the figure, DE ||BC, ∠A=30° and∠B=50°. Find the values of x, y and z.
Attachments:
Answers
Answered by
78
this is the correct answer
Attachments:
Answered by
85
Solution :
1 ) In ∆ABC,
<A + <B + <C = 180°
[ Angle sum property ]
=> 30° + 50° + z = 180°
=> 80° + z = 180°
=> z = 180° - 80°
=> z = 100°
2 ) In ∆ABC ,
DE // BC ,
BD is a transversal ,
y° = <B = 50° [ corresponding angles ]
3 ) DE // BC , CE is a transversal,..
x = z = 100° [ corresponding angles ]
Therefore ,
x = 100° , y = 50° , z = 100°
••••
1 ) In ∆ABC,
<A + <B + <C = 180°
[ Angle sum property ]
=> 30° + 50° + z = 180°
=> 80° + z = 180°
=> z = 180° - 80°
=> z = 100°
2 ) In ∆ABC ,
DE // BC ,
BD is a transversal ,
y° = <B = 50° [ corresponding angles ]
3 ) DE // BC , CE is a transversal,..
x = z = 100° [ corresponding angles ]
Therefore ,
x = 100° , y = 50° , z = 100°
••••
Similar questions