In the figure find the total current supplied to the circuit by the battery.
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hi sonia...just take 6 ohm and 3 ohm resistors in parallel and take the equivalent resistance of them i.e. 2 ohm in series with 4 ohm., you will get equivalent resistance of 6ohm now take it in parallel combination with the 3 ohm resistance , your equivalent resistance will be 2 ohm. now use the relationship I =V/R. you will get 6/2= 3A
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15
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4
Use Ohm's law
V= IR
R=R1+R2+R3=3+4+6
6= I×13
6/13Ampere=I(Current)
(May be its correct)
V= IR
R=R1+R2+R3=3+4+6
6= I×13
6/13Ampere=I(Current)
(May be its correct)
no it is incorrect.... correct answer is 4A
could u prove it??
answer written in my book is 4A
explain me. I wanna learn
how can I explain??
I've only asked this doubt.
ok i'll try to understand
hi sahil, you should know that each resistance contains nodes at back and forth position so, each branch will contain distinct current...if you just simplify this figure in a simple rectangular circuit the you will know where to use parallel combination and where to put sereis combination...
ThankYoU Very Much
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