In the figure given below, AO = BO and angle A = angle
B.
a. Is angle AOC = angle BOD? Why?
b. Is triangle AOC congruent to triangle BOD? Give reasons.
c. Is angle ACO = angle BDO? Why?
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a) ∠AOC = ∠BOD (Vertically Opposite Angles) - ①
b) In ∆ AOC AND ∆ BOD
∠OAC = ∠OBD (Given)
AO = BO (Given)
∠AOC = ∠BOD (From - ①)
Therefore, ∆AOC ≅ ∆BOD by ASA Congruence Rule.
c) ∠ACO = ∠BDO by CPCT
Full Forms -
• ASA - Angle-Side-Angle Congruence Rule
• CPCT - Congruent Parts Of Congruent Triangles.
Hope It Helps
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