Question

IN THE FIGURE ,<CAO=<BDO. PROVE THAT AC.OB=BD.OC​

Answer 1

Step-by-step explanation:

in triAoc and triDob

we will similar these two triangles

<A=<D(given

<o=<o(vert opp angle)

:tri Aoc ~tri dob(by A A A)

NOW

AC/OC=DB/OB

AC×OB=BD×OC

PROVED