Question

In the figure 'O' is the centre .ABC is an equilateral triangle . find angle BAC and angle ABO​

Answer 1

Answer:

angle BOC is equal to 120 degrees

Step-by-step explanation:

triangle ABC is an equilateral triangle (given)

therefore angle ABC = angle BAC = angle ACB = 60 degrees

angle BOC = 2(BAC). becauseTheorem 8 : The angle subtended by an arc at the centre is double the angle subtended by it at any point on the remaining part of the circle.

= 2(60)

= 120degrees

mark answer as brainliest

Answer 2

Answer:

< BAC = 60° and < ABO = 30°

Step-by-step explanation:

Since the triangle ABC is an equilateral triangle,

< ABC = 60°

< BAC = 60° & < BCA = 60°

Join OA. Then consider triangle ABO.

< BOA = 120° ( The angle made by an arc of a circle on the alternative arc is half the angle made by it's centre. Here < BCA = 60° )

Therefore, In ∆ ABO,

< ABO = < BAO = (180° - 120°) / 2 ( Since the sides are equal (radius OB = OA) it's corresponding

angles are also equal)

= 60° / 2

= 30°

Hence the Result