Question

in the figure O is the centre of the circle and angle ACD =30°.Find:angleBAD​

Answer 1

Answer:

angleACD= angleABD=30°. [angles in the same segment]

angleADB=90°.

in triangleABC

[ angle in a semi circle]

angleABD+angleADB+angleBAD=180°. [ angle sum property]

angleBAD=60°

construction- Join OD

angleAOD=2angleACD. [angle at the

centre is twice the corresponding inscribed angle]

angleAOD=60°

Hope it helps