In the figure P is a point on the bisector of angle ABC, PQ perpendicular BA and PR perpendicular BC.Prove that PQ=PR
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in triangle BPQ and triangle BPR
Angle BQP = Angle BRP = 90°
Angle QBP= Angle RBP ( BCOZ pb is the bisector of angle ABC)
PB = PB (COMMON)
HENCE both the triangles are congruent to each other.
so, PQ= PR (by cpct)
Angle BQP = Angle BRP = 90°
Angle QBP= Angle RBP ( BCOZ pb is the bisector of angle ABC)
PB = PB (COMMON)
HENCE both the triangles are congruent to each other.
so, PQ= PR (by cpct)
vernon10112:
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