Question

In the figure, the parallel lines l and m are cut by a transversal n. If angle 1 and angel 2 are (5x-10) and (3x+60) respectively, then find the measures of angle 1 and angle 2.

Answer 1

Where is 1 and 2, u must draw a figure If 1 and 2 are linear pair Angle 1 + angle 2 =180 5x-10+3x+60=180 8x+50=180 8x=180-50 8x= 130 x =130/8 x=65/4 Now Angle 1 = 5x-10 = 5*65/4-10 =(325-40)/4 = 285/4 Angle 2 = 3x+60 Substitute x =65/5 and simplify

Answer 2

You'll have to  find out if the angles are alternate angles or corrosponding angles or vertically opposite angles . Once you find the reason you can form a linear equation and find the " x " then you can find out the angles.
(3x+60) =(5x-10) 
=> 3x+60 = 5x-10
=> 3x-5x = -10 - 60 
=> -2x = -70
=> 2x = 70 ( multiplying both sided by (-) 
=> x = 70/2
=> x = 35 
Therefore , angle 1 = 5x - 10 
                              => 165 degrees 
                  angle 2 = 3x+60 
                               => 165 degrees