the curved surface area of a right circular cylinder of height 14 cm is 88 cm2 .find the diameter of the base of cylinder
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Answered by
10
Let r be the radius of the base and h = 14 cm be the height of the cylinder.
Curved surface area of cylinder = 2πrh = 88 cm2
⇒ 2 × 22/7 × r × 14 = 88
⇒ r = 88/ (2 × 22/7 × 14)
⇒ r = 1 cm
Thus, the diameter of the base = 2r = 2×1 = 2cm
Curved surface area of cylinder = 2πrh = 88 cm2
⇒ 2 × 22/7 × r × 14 = 88
⇒ r = 88/ (2 × 22/7 × 14)
⇒ r = 1 cm
Thus, the diameter of the base = 2r = 2×1 = 2cm
Answered by
6
CSA of a cylinder is 2pirh
given, h=14 and CSA is 88 cm2
so, 2×22/7×r×14=88
r=88×7/2×22×14
r=1
d=2r
d=2×1
so,d=2
given, h=14 and CSA is 88 cm2
so, 2×22/7×r×14=88
r=88×7/2×22×14
r=1
d=2r
d=2×1
so,d=2
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