in the figure triangle ADB and triangle cdb are on the same base DB if AC and BD intersect at O then prove that area of triangle ADB upon area of triangle CBD is equals AO upon CO
Answers
Explanation:
Given that ΔADB and ΔCDB are on the same base DB.
Also, given that AC and BD intersect at O.
To prove that
Since, we know that the area of the triangle can be determined using the formula,
Now, we shall draw and
Thus, the area of the ΔADB is given by
The area of ΔCDB is given by
Dividing the two triangles, we have,
Cancelling the common terms, we get,
----------- (1)
Now, let us consider the ΔAOE and ΔCOF
From the triangles, we can see that,
∠AEO = ∠CFO (right angles)
Also, we can see that,
∠AOE = ∠COF (vertically opposite angles)
Then, by AA Similarity Criterion, we have,
Also, we know that if two trianlges are similar then their corresponding sides are in the same ratio.
Thus, we have,
-----------(2)
Substituting the equation (2) in equation (1), we have,
Hence proved
Learn more:
(1) In the figure given below, ABC and DBC are two triangles on the same base BC. if AD is intersect BC at O then show that :ar(ABC)/ar(DBC) = AO/DO
brainly.in/question/5825734
(2) Question 4 In the given figure, ABC and ABD are two triangles on the same base AB. If line-segment CD is bisected by AB at O, show that ar (ABC) = ar (ABD).
Class 9 - Math - Areas of Parallelograms and Triangles Page 162"
brainly.in/question/1427774
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