Question

Spherical ball of radius 8 cm is cut into 4 equal parts what is the total surface area of the parts​

Answer 1

Answer:

Volume of large sphere = $\tt{\frac{4}{3} \pi r^{3}}$

= $\tt{\frac{4}{3} \times \frac{22}{7} \times 8^{3}}$

= 4 × 11264/21 cu cm

Volume of 4 parts = 4 × 11264/21 ÷ 4

= $\tt{\frac{11264}{21}}$ cu cm

When volume = 11264/21 , radius:

$\tt{\frac{4}{3} \pi r^{3} = \frac{11264}{21}}$

=> r^3 = 128 cm

=> $\tt{r = \sqrt[3]{128}}$ cm

Total surface area of smaller part = $\tt{4 \pi r^{2}}$

= $\tt{4 \times \frac{22}{7} \times 128^{\frac{2}{3}}}$

= 319.16 sq cm

Total surface area of 4 parts = 319.16 × 4

= 1276.64 sq cm

Hope it Helps!!