In the following figure; P and Q are the points
of intersection of two circles with centres O
and O'. If straight lines APB and COD are parallel to 00': prove:
(1) 00' = AB/2
(2) AB - CD
please reply very important
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Answer:
Step-by-step explanation:
Drop OM and O'N perpendicular on AB and OM' and O'N' perpendicular on CD
Answered by
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00' = AB/2 & AB = CD
Step-by-step explanation:
Lets draw OM ⟂ CD and O'N ⟂ CD
OM ⟂ CD
⇒ CM = QM = CQ/2 ( as perpendicular from center bisect the chord)
⇒ CQ = 2MQ
Similarly, O'N ⟂ CD
⇒ QN = ND = QD/2
⇒ QD = 2NQ
CD = CQ + QD
= 2MQ + 2NQ = 2(MQ +NQ) = 2MN
MN = OO'
CD = 2OO'
=> OO' = CD/2
Similarly we can show that
OO' = AB/2
AB = CD = 2 OO'
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