Question

In the following situation, do the. list of numbers involved form an AP. "The fee charged every month by a school from classes 1 to 10, when the monthly fee for class 1 is 250 rupees and it increases by 150 rupees for the next higher class.​

Answer 1

Answer:

a=250

d=150

the total fee collected per month is the sum of all the charges fees

Sn=n/2(2a+(n-1)d)

=10/2(2×250+9×150)

=5×(500+1350)

=5×1850

=9250

this your answer

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Answer 2

Fee charged by class 1 = 250

Fee charged by class 2 = 250+150 =400

Fee charged by class 3 = 400 + 150 = 550

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Clearly , the following list of nos. form an A.P.

Total money collected = S10

$= \frac{n}{2} (2a + (n - 1)d)$

$= 5(500 + 9 \times 50)$

$= 5(500 + 450)$

$= 5 \times 950$

$= 4750$