In the given fig a circle is inscribed in an equilateral triangle abc of side 12 find the radius of the inscribed circle
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5
we know that side =12
the circle is inscribed in that equilateral triangle
so length of side is equal to diameter of circle so radius = 6
the circle is inscribed in that equilateral triangle
so length of side is equal to diameter of circle so radius = 6
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2
side of the triangle=12
it becomes diameter of circle
radius=6
it becomes diameter of circle
radius=6
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