in the given figure a circle with center o is given in which a diameter AB bisects the chord CD at a point E such that CE= ED= 8cm and EB = 4cm. find the radius of the circle.
SohamPatil:
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Let the radius of circle be x cm
OE=x-4
OC=x
CE=8cm
In triangle OCE
By pythagoras theorem
OC = CE +OE
OC =64+x^2-4x +16
x^2=64 +x^2-4x+16
4x=80
x=20
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