Question

In the given figure, AB = 8cm, BC = 3cm and BE is parallel to CD.

(i) FIND—
a) BE/CD ,
b) area of ∆ABC/area of quadrilateral BCDE

(ii) What is the special name given to the quadrilateral BCDE?.​

Answer 1

Answer:

6AM the world of godess is not a sin a woman will be in heaven for the equality of godess or the godess that

Answer 2

Answer:

Perimeter of the quadrilateral =10+8+5+13=36cm

Area of the quadrilateral=area of the triangle ABD+area of the triangle DBC.

Area of the triangle DBC=

2

1

×B×H

=

2

1

×5×12

=30cm

2

Area of the Triangle ABD=

s(s−a)(s−b)(s−c)

Here, s=

2

10+12+8

=15cm

Therefore area=

15(15−10)(15−12)(15−8)

=15

7

cm

2

Therefore area of the quadrilateral=15+15

7

=15(1+

7

)cm

2