Question

in the given figure AB BC and CD are equal chords of a circle with the centre o and AD is the diameter if angel DEF is 110 degree find angle AEF

Answer 1

Answer:

m∠AEF = 20°

Step-by-step explanation:

Foe better understanding of the solution, see the attached diagram of the problem :

Given : AB = BC = CD, AD is the diameter of the circle.

m∠DEF = 110°

To find : m∠AEF

Solution : Since, AD is the diameter of the circle

⇒ m∠AED = 90° ( Angle formed in the semicircle is 90°)

Now, m∠AEF + m∠AED = m∠DEF

m∠AEF + 90° = 110°

⇒ m∠AEF = 110° = 90°

⇒ m∠AEF = 20°

Answer 2

Answer:

20 ° mark it as brainliest answer