In the given figure, AB is a chord of a circle with centre O and AB is produced to C such that BC = OB. Also, CO is joined and produced to meet the circle in D. If ∠ACD = 25°, then ∠AOD =?
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BOC+BCO=ABO
ABO=25°+25° (∆OBC is an isosceles triangle)
ABO=50°
i.e OAB=OBA=50°
Hence AOB = 80°
therefore,
AOD+AOB+BOC =180°
AOD+80+25=180°
AOD=180-105=75°
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