Question

in the given figure ab is a diameter of the circle and AC =BC, then find angle CAB

Answer 1

AngleACB=90(as we know angle made by an diameter in the circumference is 90)
And AC=BC
so,AngleACB=CBA
Let ACB=CBA=X
now,X+X+AngleACB
X+X+90=180
2X=180-90
2X=90
X=90/2
X=45
Hence,AngleCAB=AngleCBA=45

Answer 2

Answer:

We know that the angle at circumference subtended by the diameter of the circle is right angle.

Thus ∠ACB=90

In △ABC

 AC=BC (given)

=>∠CAB=∠CBA

Now,

 ∠CAB+∠CBA+∠ACB=180  

 

=>∠CAB+∠CAB=180−90

=>∠CAB=  90/2

=>∠CAB=45  

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Step-by-step explanation: