In the given figure, AB is diameter of the circle and O is the
centre. If the measure of angleCOB = 40°, then the measure of
angleCAB will be:
(a) 20°
(b) 30°
(c) 40°
(d) 60°
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The Angle CAB will be (a) 20°
As AB is a straight line,
Angle COB + COA = 180°
Therefore, Angle COA = 140°
In triangle OAC,
OA = OC (radius of the circle)
So Angle OAC = OCA
OAC = CAB (same angles)
Using sum of angles of a triangle,
Angle COA + OAC + OCA = 180°
140° + 2 OAC = 180°
OAC = CAB = 20°
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