in the given figure AB parallel to CE find the value of x and y
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y+10=24(corresponding angles are equal)
y=24-10=14
Angle ACB=180-(92+24)=64
In triangle ABC:-
Ang ABC+ang BAC+angle X=180
X=180-(24+64)=180-88=92
X=92,y=14
y=24-10=14
Angle ACB=180-(92+24)=64
In triangle ABC:-
Ang ABC+ang BAC+angle X=180
X=180-(24+64)=180-88=92
X=92,y=14
Ràshmij:
I don't understand how they were corresponding Angles please tell me
thanks a lot
now i understand
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