Question

In the given figure ∆ABC and ∆DCB are right triangle at A and D

respectively and AC=DB. Prove that ∆ABC≈∆DCB.​

Answer 1

Answer:

△ABC and △DCB both are right angled triangle.

⇒ Both triangle have common hypotenuse.

⇒ In △ABC and △DCB

⇒ AC=DB [Given]

⇒ BC=CB [Common side]

∴ △ABC≅△DCB [By RHS property]

⇒ RHS property does not present in option