Question

In the given figure ABC is a rt. angled triangle with angle B=90°. If AD=17 cm,AB=15 cm and CD=12 cm. Find
i)BD
ii)AC
Step by step explanation

Answer 1

Step-by-step explanation:

THE ANSWER IS IN THE ATTACHMENT

THE ANSWER IS IN THE ATTACHMENTHOPE IT HELPS YOU!!

Answer 2

(i)BD=8cm

(ii) AC=25cm

Step-by-step explanation:

In triangle ABC

Angle B=90 degrees

AB=15cm ,AD=17cm and CD=12cm

In triangle ABD

$AD^2=AB^2+BD^2$

Using Pythagoras theorem

$(Hypotenuse)^2=(base)^2+(Perpendicular\;side)^2$

Substitute the values then we get

$(17)^2=(15)^2+BD^2$

$289=225+BD^2$

$BD^2=289-225=64cm^2$

$BD=\sqrt{64}=8cm$

(i)BD=8 cm

(ii) In triangle ABC

BC=BD+CD=8+12=20cm

$AC^2=AB^2+CB^2$

$AC^2=(15)^2+(20)^2$

$AC^2=225+400=625$

$AC=\sqrt{625}=25cm$

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