Question

In the given figure, ABCD is a
cyclic quadrilateral. ZBDC
50°, ZCAD = 70°. What is the
measure of ZBCD?​

Answer 1

$\huge\underline\red{Given\::-}$

• ABCD is a cyclic quadrilateral.
• BDC = 50°
• CAD = 70°

$\huge\underline\blue{To\:Find\::-}$

• measure of BCD

$\huge\underline\green{Solution\::-}$

=> BDC = BAC (angles in the same segment are equal)

=> BAC = 50°

=> BAD = CAD + BAC

=> BAD = 70° + 50°

=> BAD = 120°

As ABCD is a cyclic quadrilateral.

BAD + BCD = 180°

120° + BCD = 180°

BCD = 180° - 120°

$\fcolorbox{</em><em>green</em><em>}{</em><em>orange</em><em>}{</em><em>BCD\</em><em>:</em><em>=</em><em>\</em><em>:</em><em>6</em><em>0</em><em>°</em><em>}$

please mark as brainliest.....................!

Answer 2

Given:−

ABCD is a cyclic quadrilateral.

BDC = 50°

CAD = 70°

ToFind:−

measure of BCD

Solution:−

=> BDC = BAC (angles in the same segment are equal)

=> BAC = 50°

=> BAD = CAD + BAC

=> BAD = 70° + 50°

=> BAD = 120°

As ABCD is a cyclic quadrilateral.

BAD + BCD = 180°

120° + BCD = 180°

BCD = 180° - 120°