in the given figure ABCD is a rhombus in which angle BCD is 100, find the value of angle x+y ?
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Answered by
49
as rhombus is a parallelogram
AB//DC
So,x+y+100=180°(co-interior angles)
x+y=80°
AB//DC
So,x+y+100=180°(co-interior angles)
x+y=80°
Answered by
18
we know that the sum of consecutive interior angle is 180°.
therefore,
x+y=180-100
orx+y=80
therefore,
x+y=180-100
orx+y=80
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