Question

In the given figure ABCD is a trapezium in which AB//BC angle ABC =90 AD=16cm AC=41cm and BC=40cm. Find the area of the trapezium

Answer 1

Where is The Figure.

If There will be no Figure then Answer Couldn't be told

Answer 2

$\large\underline\pink{Diagram:-}$

$\large\underline\pink{Given:-}$

• ABCD is a trapezium in which AB//BC angle ABC =90 AD=16cm AC=41cm and BC=40cm.

$\large\underline\pink{To find:-}$

• Find the area of the trapezium....?

$\large\underline\pink{Solutions:-}$

ABCD is a trapezium.

<ABC = 90°

from the right ∆ ABC, we have:-

⟹ AB² = (41)² - (40)²

⟹ AB² = 1681 - 1600

⟹ AB² = 81

⟹ AB = √81

⟹ AB = 9cm

Length AB = 9cm

Now,

Area of the trapezium = 1/2 × (AB + BC) × AB

⟹ 1/2 × (16 + 40) × 9

⟹ 1/2 × 56 × 9

⟹ 28 × 9

⟹ 252cm²

Hence, the area of the trapezium is 252cm²