Question

IN the given figure ,AD DIVIDES ANGLE BAC in the ratio 1:3 AND AD=DB. DETERMINE the value of X.

Answer 1

Solution: Let the ratio multiple be 3y and y.

As per the figure, 108+3y+y=180 (sum of angles of straight line).

This implies, 4y=180-108=72, => y=72/4 = 18.

Therefore, angle CAD = 3*18 =54 and total angle BAC = 54+18=72.

Now, in triangle BAC, 72 + 18 + x =180, => x =180-90 = 90.

Answer 2

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