Question

In the given figure,angleCAB = 40°,AC = AB and BC = BD.Find:
¡]angleACB
¡¡]angleCDB​

Answer 1

Answer:

acb+cab+abc=180°

40°+x+x=180°

x=70°

acb°70°

cbd=180°-70°

=110°

as,bd=cb

bdc=180°-110°/2

=35°

Step-by-step explanation:

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