In the given figure APBC is quadrant of a circle of radius 14cm and semicirce is drawn with BC as diameter. Find the area of shaded region?
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Answer:
π R² / 8 = π * 98 cm² for R = 14 cm.
Step-by-step explanation:
see the diagram enclosed.
ABC is the quadrant. BC is a radius R of the given circle. Now a semicircle is drawn in the quadrant with BC as the diameter and R/2 as its radius.
So shaded area 1 = 1/2 * π (R/2)² = π R²/8
Area of quadrant ABC = 1/4 * π R²
Shaded area2 = 1/8 * πR²
Substitute R = 14 cm now.
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