Question

In the given figure, ∠B < ∠A and ∠C < ∠D. Show that AD < BC.​

Answer 1

Answer:

Let the point of intersection of BC and AD be O

In △ABO

⇒∠B<∠A

Thereore, ⇒AO<BO (1) (side opposite to greater angle is largest)

Similarly,

In △COD

⇒∠C<∠D

Thereore, ⇒DO<CO (2) (side opposite to greater angle is largest)

Adding (1) and (2) we get,

⇒BO+OC>AO+DO

⇒BC>AD

Answer 2

Step-by-step explanation:

Search for questions & chapters

Class 9

>>Maths

>>Triangles

>>Inequalities in a Triangle

>>In the given figure, B < ...

Question

Bookmark

In the given figure, ∠B<∠A and ∠C<∠D, show that AD<BC.

1091066

expand

Medium

Solution

verified

Verified by Toppr

Let the point of intersection of BC and AD be O

In △ABO

⇒∠B<∠A

Thereore, ⇒AO<BO (1) (side opposite to greater angle is largest)

Similarly,

In △COD

⇒∠C<∠D

Thereore, ⇒DO<CO (2) (side opposite to greater angle is largest)

Adding (1) and (2) we get,

⇒BO+OC>AO+DO

⇒BC>AD

Hence proved